Precalculus Practice Test: Rational Functions and Asymptotes
- Rational Functions and Asymptotes
- 10 questions
- 15 minutes
These 10 questions cover vertical, horizontal and slant asymptotes, holes, intercepts and rational equations and inequalities. Always factor first: a factor that cancels gives a hole, a factor that stays in the denominator gives a vertical asymptote.
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Question 1
What is the vertical asymptote of f(x) = x + 2x − 5?
Correct answer: B
The denominator is zero at x = 5 and the numerator is not zero there, so the line x = 5 is a vertical asymptote. At x = −2 the function has an x-intercept, not an asymptote.
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Question 2
What is the horizontal asymptote of f(x) = 3x2 − 16x2 + x?
Correct answer: C
The degrees of the numerator and denominator are equal, so the asymptote is the ratio of leading coefficients: 3/6 = 1/2. The line y = 0 applies only when the denominator has the higher degree.
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Question 3
Which feature does the graph of f(x) = x2 − 9x − 3 have at x = 3?
Correct answer: A
The expression simplifies to x + 3 for x ≠ 3, so the graph is a line with one missing point at (3, 3 + 3) = (3, 6). The factor cancels, so there is no vertical asymptote.
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Question 4
What is the slant (oblique) asymptote of f(x) = x2 + 3x − 1x − 1?
Correct answer: D
Long division gives x2 + 3x − 1 = (x − 1)(x + 4) + 3, so f(x) = x + 4 + 3/(x − 1), and the last part goes to 0. The line y = x + 2 comes from dividing by x + 1 instead of x − 1.
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Question 5
What is the horizontal asymptote of f(x) = 5xx2 + 1?
Correct answer: B
The denominator has the higher degree, so the fraction approaches 0 for large |x|. The value 5 would be the asymptote only if both degrees were equal.
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Question 6
What are the x-intercepts of f(x) = x2 − 4x2 − x − 6?
Correct answer: A
Factor: (x − 2)(x + 2) / ((x − 3)(x + 2)). The factor x + 2 cancels, so x = −2 is a hole, not an intercept, and only x = 2 makes the function zero.
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Question 7
What is the solution of 2x − 1 = 3x + 2?
Correct answer: C
Cross-multiplying gives 2(x + 2) = 3(x − 1), so 2x + 4 = 3x − 3 and x = 7. Neither denominator is zero at 7, so the solution is valid.
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Question 8
Which function has vertical asymptotes x = 2 and x = −2 and the horizontal asymptote y = 0?
Correct answer: D
The denominator x2 − 4 is zero at ±2, nothing cancels, and the bottom degree is higher, so y = 0. With x − 2 on top, the factor cancels and x = 2 becomes a hole.
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Question 9
What is the domain of f(x) = x + 1x2 + 5x + 6?
Correct answer: A
The denominator factors as (x + 2)(x + 3), which is zero at −2 and −3. The numerator does not affect the domain, so −1 is allowed.
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Question 10
What is the solution set of x − 4x + 1 ≤ 0?
Correct answer: C
The quotient is negative between the critical values −1 and 4 and equals 0 at x = 4. The value −1 must be excluded because it makes the denominator zero.
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